document.write( "Question 263025: Please explain and solve. Thank you.
\n" ); document.write( "A rain gutter is made from sheets of aluminum that are 20 inches wide. Determine the depth of the gutter that will allow a cross-sectional area of 13 square inches. Show that there are 2 different solutions to the problem. Round to the nearest tenth of an inch.
\n" ); document.write( "x(20+2x)= 13.
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Algebra.Com's Answer #193779 by stanbon(75887)\"\" \"About 
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A rain gutter is made from sheets of aluminum that are 20 inches wide. Determine the depth of the gutter that will allow a cross-sectional area of 13 square inches. Show that there are 2 different solutions to the problem. Round to the nearest tenth of an inch.
\n" ); document.write( "x(20+2x)= 13.
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\n" ); document.write( "The cross-section is a slice thru the gutter from top thru the bottom.
\n" ); document.write( "The shape is a \"U\".
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\n" ); document.write( "If height = base = x inches you get x^2 = 13 and x = sqrt(13)
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\n" ); document.write( "If base is x then height is (20-x)/2:
\n" ); document.write( "x(20-x)/2 = 13
\n" ); document.write( "20x - x^2 = 26
\n" ); document.write( "x^2 -20x + 26 = 0
\n" ); document.write( "x = [20 +- sqrt(400 - 4*1*26)]/2
\n" ); document.write( "x = [20 +- sqrt(296)]/2
\n" ); document.write( "x = [20 + 17.2]/2 = 37.2/2 = 18.6\"
\n" ); document.write( "OR
\n" ); document.write( "x = [20 - 17.2]/2 = 1.4\"
\n" ); document.write( "---
\n" ); document.write( "So base could be 18.6 and height be (1.4/2) = 0.7\"
\n" ); document.write( "Or base could be 1.4\" and height be (18.6/2) = 9.3\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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