document.write( "Question 263025: Please explain and solve. Thank you.
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document.write( "A rain gutter is made from sheets of aluminum that are 20 inches wide. Determine the depth of the gutter that will allow a cross-sectional area of 13 square inches. Show that there are 2 different solutions to the problem. Round to the nearest tenth of an inch.
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document.write( "x(20+2x)= 13. \n" );
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Algebra.Com's Answer #193779 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A rain gutter is made from sheets of aluminum that are 20 inches wide. Determine the depth of the gutter that will allow a cross-sectional area of 13 square inches. Show that there are 2 different solutions to the problem. Round to the nearest tenth of an inch. \n" ); document.write( "x(20+2x)= 13. \n" ); document.write( "---------------------- \n" ); document.write( "The cross-section is a slice thru the gutter from top thru the bottom. \n" ); document.write( "The shape is a \"U\". \n" ); document.write( "---- \n" ); document.write( "If height = base = x inches you get x^2 = 13 and x = sqrt(13) \n" ); document.write( "-------------------------------------------- \n" ); document.write( "If base is x then height is (20-x)/2: \n" ); document.write( "x(20-x)/2 = 13 \n" ); document.write( "20x - x^2 = 26 \n" ); document.write( "x^2 -20x + 26 = 0 \n" ); document.write( "x = [20 +- sqrt(400 - 4*1*26)]/2 \n" ); document.write( "x = [20 +- sqrt(296)]/2 \n" ); document.write( "x = [20 + 17.2]/2 = 37.2/2 = 18.6\" \n" ); document.write( "OR \n" ); document.write( "x = [20 - 17.2]/2 = 1.4\" \n" ); document.write( "--- \n" ); document.write( "So base could be 18.6 and height be (1.4/2) = 0.7\" \n" ); document.write( "Or base could be 1.4\" and height be (18.6/2) = 9.3\" \n" ); document.write( "==================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |