document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32929>Question 32929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation.<BR>\n" );
document.write( "4x-1 / x^2+5x-14 = 1/x-2 - 2/x+7<BR>\n" );
document.write( "Solve the system of equations.<BR>\n" );
document.write( "1.)   y= -5x-2<BR>\n" );
document.write( "      y= -3x\r<BR>\n" );
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document.write( "2.)   3x - y = 5<BR>\n" );
document.write( "     -4x + y = -5\r<BR>\n" );
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document.write( "3.)    2x - y = -1<BR>\n" );
document.write( "       2x + z = -6<BR>\n" );
document.write( "       3y - z = 7\r<BR>\n" );
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document.write( "I really need help on these problems I have done these problems over and over again until I am getting frustrated with myself.  I need help.  I am not sure if you are supposed to plug in the -3x into the other problem in question one.  I am not sure if you are supposed to just add the x and y values and then solve for y in problem 2.  Are you supposed to use cramers rule for problme three.  Please help me I am struggling with these problems.  I need somebody to help understand the process of each problem so I will understand the problems come test time on Monday. Thanks for your time and help it is greatly appreciated.\r<BR>\n" );
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document.write( "Hilary </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19377 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4x-1)/(x~2+5x-7)=1/(x-2)-2/(x+7) or (4x-1)/(x+7)(x-2)=1/(X-2)-2/(X+7) OR\r<BR>\n" );
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document.write( "(4X-1)/(X+7)(X-2)=((X+7)-(2X+4))/(X+7)(X-2) or 4x-1=x+7-2x+4 or 5x=12 or x=12/5\r<BR>\n" );
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document.write( "proof (4(12/5)-1)/(12/5)~2+5(12/5)-7=1/((12/5)-2)-2/((12/5+7) or<BR>\n" );
document.write( "(48/5-1)/((12/5)~2+(12/5)+7)=1/((12/5)-2)-2/((12/5)+7) or 43/5=12/5+7-2(12/5)+4 <BR>\n" );
document.write( "or 43/5=12/5+7-24/5+4 or 43/5=12/5+11-24/5 or 43/5=-12/5+11 or 55/5=11 or 11=11\r<BR>\n" );
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document.write( "y=-5x-2<BR>\n" );
document.write( "y=-3x substituting y=-3x in equation #1 we get<BR>\n" );
document.write( "-3x=-5x-2 or 2x=-2 or x=-1 then y=-5(-1)-2 or y=+5-2 or y=3\r<BR>\n" );
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document.write( "proof 3=-3(-1) or 3=3 and 3=-5(-1)-2 or 3=5-2 or 3=3\r<BR>\n" );
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document.write( "3x-y=5<BR>\n" );
document.write( "-4x+y=-5 adding these two equztions we get<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "-x=0 substituting 0 for y in equation #1 we get<BR>\n" );
document.write( "3*0-y=5 or y=-5 <BR>\n" );
document.write( "proof -4*0-5=-5 or -5=-5 and 3*0-(-5)=5 or 5=5\r<BR>\n" );
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document.write( "2x-y=-1<BR>\n" );
document.write( "2x+z=-6<BR>\n" );
document.write( "3y-z=7 adding equation #2 & #3 we get<BR>\n" );
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document.write( "2x+3y=1 subtracting this equation from equztion #1 we get<BR>\n" );
document.write( "2x-y=-1<BR>\n" );
document.write( "-2x-3y=-1<BR>\n" );
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document.write( "-4y=-2 or y=1/2 then 2x-(1/2)=-1 or 2x=-1/2 or x=-1/4 therefore 3(1/2)-z=7 or<BR>\n" );
document.write( "3/2-z=7 or -z=7-3/2 or z=-11/2<BR>\n" );
document.write( "x=-1/4, y=1/2 & z=-11/2 </SPAN>\n" );
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