document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262968>Question 262968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the total distance of a journey is 120 km .If one goes by 60 kmph and comes back at 40kmph what is the average speed during the journey? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193767 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193767\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is not (60+40)/2=50<BR>\n" );
document.write( "Why? because the times at each speed are different.\r<BR>\n" );
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document.write( "It will be close to 50 though since the difference in times is so small.<BR>\n" );
document.write( "60*x=120<BR>\n" );
document.write( "40*y=120<BR>\n" );
document.write( "x=2 hrs<BR>\n" );
document.write( "y=3 hrs<BR>\n" );
document.write( "total distance over total time<BR>\n" );
document.write( "total time is 5 hours<BR>\n" );
document.write( "120+120=240 total distance\r<BR>\n" );
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document.write( "240/5=48 kph\r<BR>\n" );
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