document.write( "Question 262971: City A's population is 68000, decreasing at a rate of 80 people per year. City B having population 42000 is increasing at a rate of 120 people per year. In how many years both the cities will have same population? \n" ); document.write( "

Algebra.Com's Answer #193754 by sunitha.pratapani(4) $\"\"$ $\"About$

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city A population =68000
\n" ); document.write( " amount of decrease =68000-80X
\n" ); document.write( " city B population=42000
\n" ); document.write( " Amount of increase=42000+120x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " if both cities will have same population then
\n" ); document.write( " 68000-80x=42000+120x\r
\n" ); document.write( "\n" ); document.write( " 68000-42000=120x+80x
\n" ); document.write( " 26000 = 200x
\n" ); document.write( " x= 26000/200
\n" ); document.write( " 130 \r
\n" ); document.write( "\n" ); document.write( "in 130 years both cities will have same population
\n" ); document.write( "check: city A population=68000-80* 130
\n" ); document.write( " 68000-10400
\n" ); document.write( " 57600
\n" ); document.write( " city B population = 42000+ 120*130
\n" ); document.write( " 42000+15600
\n" ); document.write( " 57600 \n" ); document.write( "

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