document.write( "Question 262989: A 25-foot ladder reaches 24 feet up the side of building. Then the top of the ladder slides down 4 feet. How many additional feet does the bottom of the ladder slide out from the base of the building?\r
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Algebra.Com's Answer #193736 by mananth(16946)\"\" \"About 
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A 25-foot ladder reaches 24 feet up the side of building. Then the top of the ladder slides down 4 feet. How many additional feet does the bottom of the ladder slide out from the base of the building?\r
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\n" ); document.write( "\n" ); document.write( "25^2= 24^+x^2 x distance from the wall\r
\n" ); document.write( "\n" ); document.write( "625-576=49\r
\n" ); document.write( "\n" ); document.write( "Sqrt49=7\r
\n" ); document.write( "\n" ); document.write( "The ladder is 7 ft from the wall in the first position\r
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\n" ); document.write( "\n" ); document.write( "Second position\r
\n" ); document.write( "\n" ); document.write( "Let it slide x feet.\r
\n" ); document.write( "\n" ); document.write( "Vertical slide is 4 ft : so vertical height = 20\r
\n" ); document.write( "\n" ); document.write( "25^2= 20^2 + (x+7)^2\r
\n" ); document.write( "\n" ); document.write( "625= 400 + x^2 +14x+49\r
\n" ); document.write( "\n" ); document.write( "X^2 +14x – 176=0
\n" ); document.write( "X^2 +22x-8x+176=0\r
\n" ); document.write( "\n" ); document.write( "X(x+22)-8(x+22)=0\r
\n" ); document.write( "\n" ); document.write( "(x+22)(x-8)=0\r
\n" ); document.write( "\n" ); document.write( "So x= 8\r
\n" ); document.write( "\n" ); document.write( "It slides by 8 feet.\r
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