document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262949>Question 262949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jerry is 3 years less than twice as old as Larry, The sum of their age is 60. find their ages.\r<BR>\n" );
document.write( "\n" );
document.write( "Jerry is______years old and Larry is __________years old. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193721 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193721\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let larry's age =x<BR>\n" );
document.write( "jerry = 2x-3\r<BR>\n" );
document.write( "\n" );
document.write( "2x-3+x=60<BR>\n" );
document.write( "3x=63<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "jerry = 39 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );