document.write( "Question 262958: The perimeter of a rectangle is 300 yards. What are the demensions of the rectangle if the length is 40 yards more than the width? \n" ); document.write( "
Algebra.Com's Answer #193708 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! 2x+2(x+40)=300 \n" ); document.write( "4x+80=300 \n" ); document.write( "4x=220 \n" ); document.write( "x=55 yds \n" ); document.write( "x+40= 95 yds \n" ); document.write( " |