document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262871>Question 262871</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water must be boiled away to increase the concentration of 300 gallons of a salt solution from 2%-3%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193678 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How much water must be boiled away to increase the concentration of 300 gallons of a salt solution from 2%-3%?<BR>\n" );
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document.write( "Let x = amt of water that has to boil away\r<BR>\n" );
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document.write( ".02(300) = .03(300-x)<BR>\n" );
document.write( "6 = 9 -.03x<BR>\n" );
document.write( ".03x = 9 - 6<BR>\n" );
document.write( ".03x = 3<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F.03 ALIGN=MIDDLE  ALT=\"3%2F.03\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 100 gallons </SPAN>\n" );
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