document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262870>Question 262870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The owner of a store wants to make a 30-pound mixture of two candies to sell for $3 per pound. If one candy sells for $2.95 per pound and the other for $3.10 per pound, how many pounds of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193641 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x pounds of candy A be mixed with y pounds of candy B.<BR>\n" );
document.write( "Then, total x+y = 30   ...(1)<BR>\n" );
document.write( "Next, candy A sells for $2.95 per pound and the other B for $3.10 per pound,<BR>\n" );
document.write( "He wants to sell 30-pound mixture of two candies for $3 per pound. <BR>\n" );
document.write( "So,         2.95x+3.10y = 30*3<BR>\n" );
document.write( "            2.95x+3.10y = 90  ...(2)<BR>\n" );
document.write( "(1)*2.95 => 2.95x+2.95y = 30*2.95 = 88.5   ...(3)<BR>\n" );
document.write( "(2)-(3) =>  3.10y-2.95y = 90-88.5<BR>\n" );
document.write( "            0.15y = 1.5<BR>\n" );
document.write( "            y = 1.5/0.15<BR>\n" );
document.write( "            y = 10<BR>\n" );
document.write( "(1)=> x+10=30<BR>\n" );
document.write( "      x = 30-10 = 20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );