document.write( "Question 262567: Can someone explain the steps to me for solving this equation?\r
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document.write( "x- sqrt 15-2x = 0\r
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document.write( "the solution set is?? \n" );
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Algebra.Com's Answer #193640 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Can someone explain the steps to me for solving this equation? \n" ); document.write( "x- sqrt 15-2x = 0 \n" ); document.write( "Assume the problem is \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Add \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Squaring both sides gets rid of the radical \n" ); document.write( "x^2 = 15 - 2x \n" ); document.write( ": \n" ); document.write( "Arrange as a quadratic equation \n" ); document.write( "x^2 + 2x - 15 = 0 \n" ); document.write( ": \n" ); document.write( "Factors to \n" ); document.write( "(x+5)(x-3) = 0 \n" ); document.write( ": \n" ); document.write( "Two solutions \n" ); document.write( "x = -5 \n" ); document.write( "and \n" ); document.write( "x = +3, \n" ); document.write( ": \n" ); document.write( "Check solutions in original equation \n" ); document.write( "x = 3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "3 - 3 = 0; a good solution \n" ); document.write( ": \n" ); document.write( "however when x = -5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-5 - 5 does not = 0, not a solution \n" ); document.write( " \n" ); document.write( " |