document.write( "Question 262826: I don't even know how to set up this problem. I am not finding examples, can you help please? \r
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document.write( "Events A and B are mutually exclusive events defined on a common sample space. If P (A) = 0.3
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document.write( "and P(A or B) = 0.75, find P(B).
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document.write( "(B) Events A and B are defined on a common sample space. If P(A) = 0.30, P(B) = 0.50, and P(A or
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document.write( "B) = 0.72, find P(A and B) \n" );
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Algebra.Com's Answer #193598 by Theo(13342)![]() ![]() You can put this solution on YOUR website! p(a or b) = p(a) + p(b) if a and b are mutually exclusive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if p(a) = .3 and p(a or b) = .75, then p(b) must be equal to .75 - .3 = .45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get p(a or b) = p(a) + p(b) = .3 + .45 = .75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your second problem states that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(a) = .3 \n" ); document.write( "p(b) = .5 \n" ); document.write( "p(a or b) = .72\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "find p(a and b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in this example, apparently a and b are not mutually exclusive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p (a or b) = p(a) + p(b) - p(a and b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "based on that, your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".72 = .3 + .5 - p(a and b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".72 = .8 - p(a and b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add p(a and b) to both sides of this equation and subtract .72 from both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p(a and b) = .8 - .72 = .08\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer is p(a and b) = .08\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a reference that shows you how it works.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://people.richland.edu/james/lecture/m170/ch05-rul.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "what is happening when events a and b are not mutually exclusive is that you can have cases where both events a and b occur simultaneously.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when that happens, they are being counted twice if you just add up p(a) + p(b).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "by subtracting p(a and b), you are eliminating the double counting.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |