document.write( "Question 262796: Hello, we are learning the substitution method of solving systems of equations. My equations are 4x + 5y = -6 and 2x - 10/3y = -4. I have tried it several different ways, and once got (-6,18/5) and another time (0,6/5), neither of which is correct. Please show the steps so I can find my error. Thanks!! \n" ); document.write( "

Algebra.Com's Answer #193574 by drk(1908) $\"\"$ $\"About$

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we have the following equations:
\n" ); document.write( "(i) $\"4x+%2B+5y+=+-6\"$
\n" ); document.write( "(ii) $\"2x+-+%2810%2F3%29y+=+-4\"$
\n" ); document.write( "step 1 - multiply (ii) by 3 to get
\n" ); document.write( "(iii) $\"6x+-+10y+=+-12\"$
\n" ); document.write( "step 2 - multiply (i) by 2 to get
\n" ); document.write( "(iv) $\"8x+%2B+10y+=+-12\"$
\n" ); document.write( "Notice that now, adding down with (iii) and (iv) we have y's drop out.
\n" ); document.write( "step 3 - add (iii) and (iv) together to get
\n" ); document.write( "(v) $\"14x+=+-24\"$
\n" ); document.write( "divide and we get
\n" ); document.write( " $\"x+=+-24%2F14\"$
\n" ); document.write( "when reduced gives us
\n" ); document.write( " $\"x+=+-12%2F7\"$
\n" ); document.write( "now solve for y and we get
\n" ); document.write( " $\"y+=+6%2F35\"$ \n" ); document.write( "

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