document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262783>Question 262783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How can I factor by grouping?\r<BR>\n" );
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document.write( "x3 + x2 + 2x + 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193561 by </B><A HREF=/tutors/aboutme.mpl?userid=butterfliiizzz><B>butterfliiizzz(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=butterfliiizzz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=butterfliiizzz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^3 + x^2 + 2x + 2\r<BR>\n" );
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document.write( "First we look to see if there is a greatest common factor (GCF).  x would have been the GCF, except that the last term doesn't have an x, so that won't work.  There is no GCF, so next we group terms with common factors:<BR>\n" );
document.write( "(x^3 + x^2) + (2x + 2)\r<BR>\n" );
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document.write( "Then we remove the greatest common factor of each group (and we need to make sure that there will be a common factor after this process)\r<BR>\n" );
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document.write( "x^2(x + 1) + 2 (x + 1)  Now we use the distributive property to rewrite the problem:<BR>\n" );
document.write( "(x^2 + 2) (x + 1)\r<BR>\n" );
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document.write( "The problem is now factored. </SPAN>\n" );
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