document.write( "Question 262770: If the length of a rectangle sign is to be 2 feet longer than the width and the area is to be 35 square feet, determine the length and width of the sign. \n" ); document.write( "

Algebra.Com's Answer #193547 by unlockmath(1688) $\"\"$ $\"About$

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Hello,
\n" ); document.write( "We know the area of a rectangle is width times height, right? So let's set up \"x\"
\n" ); document.write( "to represent the width so the length will be x+2. Now we can write an equation:
\n" ); document.write( "x(x+2)=35 Rewritten this will look like:
\n" ); document.write( "x^2+2x=35 Subtract 35 from both sides to be:
\n" ); document.write( "x^2+2x-35=0 Now we can factor this to get:
\n" ); document.write( "(x-5)(x+7)=0 Solve for x:
\n" ); document.write( "x=5
\n" ); document.write( "x=-7 We know this answer would not work so:
\n" ); document.write( "x=5 is our solution. So: Width is 5 feet and length is 7 feet.
\n" ); document.write( "Make sense?
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