document.write( "Question 262770: If the length of a rectangle sign is to be 2 feet longer than the width and the area is to be 35 square feet, determine the length and width of the sign. \n" ); document.write( "
Algebra.Com's Answer #193542 by drk(1908)\"\" \"About 
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Let width = x
\n" ); document.write( "and length = x + 2
\n" ); document.write( "area = LW
\n" ); document.write( "or
\n" ); document.write( "area = x(x+2) = 35
\n" ); document.write( "so, we get
\n" ); document.write( "x^2 + 2x - 35 = 0
\n" ); document.write( "factor to get
\n" ); document.write( "(x+7)(x-5) = 0
\n" ); document.write( "So,
\n" ); document.write( " x = -7 which is not possible
\n" ); document.write( "or
\n" ); document.write( "x = 5 and x + 2 = 7
\n" ); document.write( "length = 7 and width = 5
\n" ); document.write( "
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