document.write( "Question 262770: If the length of a rectangle sign is to be 2 feet longer than the width and the area is to be 35 square feet, determine the length and width of the sign. \n" ); document.write( "
Algebra.Com's Answer #193542 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Let width = x \n" ); document.write( "and length = x + 2 \n" ); document.write( "area = LW \n" ); document.write( "or \n" ); document.write( "area = x(x+2) = 35 \n" ); document.write( "so, we get \n" ); document.write( "x^2 + 2x - 35 = 0 \n" ); document.write( "factor to get \n" ); document.write( "(x+7)(x-5) = 0 \n" ); document.write( "So, \n" ); document.write( " x = -7 which is not possible \n" ); document.write( "or \n" ); document.write( "x = 5 and x + 2 = 7 \n" ); document.write( "length = 7 and width = 5 \n" ); document.write( " |