document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262741>Question 262741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a rectangular prism with dimensions w = 3, l = 4, and h = 6. If you created a second rectangular prism with the length doubled but the height halved (and the width stays the same), which would be the relation of the second volume to the first volume? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193523 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of our first prism is<BR>\n" );
document.write( "V = LWH<BR>\n" );
document.write( "or<BR>\n" );
document.write( "V = 3*4*6 = 72<BR>\n" );
document.write( "--<BR>\n" );
document.write( "The volume of the second prism is<BR>\n" );
document.write( "V = LWH<BR>\n" );
document.write( "however, we change the information and from above, we get<BR>\n" );
document.write( "V = (2L)(.5H)W<BR>\n" );
document.write( "which is<BR>\n" );
document.write( "V = (2*3)(.5*4)(6) = 6*2*6 = 72<BR>\n" );
document.write( "--<BR>\n" );
document.write( "The volumes are still the same. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );