document.write( "Question 262716: A driver travels 12 miles to work at a constant speed and travels the same distance home also at a constant speed. His speed on the trip home is 10 miles per hour faster than the trip to work and the total time for both trips is 1 hours. Find his speed on the way to work. \n" ); document.write( "
Algebra.Com's Answer #193521 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! This is an RTD problem. Here is a table based on the given information: \n" ); document.write( "Driver . . . . . . . .rate . . . . . . . . time . . . . . . . .distance \n" ); document.write( "work. . . . . . . . . R. . . . . . . . . . . .T. . . . . . . . . . . .12 . . \n" ); document.write( "home. . . . . . . . .R+10 . . . . . . . . 1-T. . . . . . . .. 12. . . \n" ); document.write( "totals. . . . . . . . . . . . . . . . . . . . .1 . . . . . . . . . . . . . . \n" ); document.write( "we have the equation \n" ); document.write( "rt = d \n" ); document.write( "solve this for t and we get \n" ); document.write( "t = d/r \n" ); document.write( "From above, \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( "The sum of the times = 1 hr, so \n" ); document.write( " \n" ); document.write( "step 1 - multiply by the common denominator of R(R+10) to get \n" ); document.write( " \n" ); document.write( "step 2 - distribute to get \n" ); document.write( " \n" ); document.write( "step 3 - combine like terms on the left to get \n" ); document.write( " \n" ); document.write( "step 4- setting = 0, we get \n" ); document.write( " \n" ); document.write( "step 5 - factoring, we get \n" ); document.write( " \n" ); document.write( "step 6 - solved for R we get \n" ); document.write( "R = 20 \n" ); document.write( "or \n" ); document.write( "R = -7 \n" ); document.write( "-- \n" ); document.write( "So, R = 20 mpg on the way to work \n" ); document.write( " |