document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262714>Question 262714</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the dimensions of a rectangle whose perimeter is 52 inches if the length is 5 inches more than twice the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193514 by </B><A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><B>vksarvepalli(154)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vksarvepalli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vksarvepalli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width be x inches\r<BR>\n" );
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document.write( "so the length will be 5+2x\r<BR>\n" );
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document.write( "now given, perimeter=52 inches\r<BR>\n" );
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document.write( "perimeter of a rectangle = twice sum of length and width\r<BR>\n" );
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document.write( "so 2(5+2x+x)=52\r<BR>\n" );
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document.write( "=> 5+3x=26<BR>\n" );
document.write( "=> 3x=21<BR>\n" );
document.write( "=> x=7<BR>\n" );
document.write( "then 5+2x will be 5+14=19\r<BR>\n" );
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document.write( "so the length is 19 inches <BR>\n" );
document.write( "and the width 7 inches  </SPAN>\n" );
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