document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262682>Question 262682</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is 30 years older than his son however he will be only thrice as old as the son after 5 years  what is father's present age ?\r<BR>\n" );
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document.write( "(a) 40 yrs    (b) 30 yrs      (c) 50 yrs      (d) none of these     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193488 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of the son = x<BR>\n" );
document.write( "Then the age of his father = x+30<BR>\n" );
document.write( "Given,father will be only thrice as old as the son after 5 years <BR>\n" );
document.write( "      x+30+5 = 3(x+5)<BR>\n" );
document.write( "      x+35 = 3x+15<BR>\n" );
document.write( "      35-15 = 3x-x<BR>\n" );
document.write( "      20 = 2x<BR>\n" );
document.write( "      2x = 20<BR>\n" );
document.write( "      x = 20/2 = 10<BR>\n" );
document.write( "Therefore the age of his father = x+30 = 10+30 = 45 years<BR>\n" );
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