document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262582>Question 262582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is one half its legth. the perimeta of rectangle is 54in </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193473 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is one half its legth. the perimeta of rectangle is 54in\r<BR>\n" );
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document.write( "let length be x<BR>\n" );
document.write( "width = ½ * x\r<BR>\n" );
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document.write( "2*(l+w)= perimeter= 54 inch\r<BR>\n" );
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document.write( "2*(3x/2)=54<BR>\n" );
document.write( "3x=54<BR>\n" );
document.write( "X= 18<BR>\n" );
document.write( "Width =9\r<BR>\n" );
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document.write( "mananth@hotmail.com<BR>\n" );
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