document.write( "Question 262649: A boy can row a boat at a constant rate of 5 mi/hr in still water, as indicated in the figure. He rows upstream for 15 minutes and then rows downstream, returning to his starting point in another 10 minutes. \r
\n" );
document.write( "\n" );
document.write( "(a) Find the rate of the current. mi/hr\r
\n" );
document.write( "\n" );
document.write( "(b) Find the total distance traveled. mi \n" );
document.write( "
Algebra.Com's Answer #193466 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A boy can row a boat at a constant rate of 5 mi/hr in still water, as indicated in the figure. He rows upstream for 15 minutes and then rows downstream, returning to his starting point in another 10 minutes. \r \n" ); document.write( "\n" ); document.write( "(a) Find the rate of the current. mi/hr\r \n" ); document.write( "\n" ); document.write( "(b) Find the total distance traveled. mi\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the distance be x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The speed upstream will be 5-x mph \n" ); document.write( "Distance traveled =1/4 *(5-x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The downstream speed will be 5+x mph \n" ); document.write( "Distance traveled = 1/6*(5+x)\r \n" ); document.write( "\n" ); document.write( "1/4* (5-x)= 1/6(5+x) ( distance traveled is the same)\r \n" ); document.write( "\n" ); document.write( "30-6x=20+4x\r \n" ); document.write( "\n" ); document.write( "10x=10 \n" ); document.write( "X = 1 mph\r \n" ); document.write( "\n" ); document.write( "D= speed * time \n" ); document.write( "Upstream = 4 *1/4 hr = 1 mile\r \n" ); document.write( "\n" ); document.write( "The distance traveled = 1+1 = 2 miles.\r \n" ); document.write( "\n" ); document.write( "mananth@hotmail.com\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |