document.write( "Question 262654: I been working on this problem all night and I am stuck. The book says the answer is 283.4 m, but I dont know how to get it. Thanks for your help\r
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document.write( "A man runs 300 m north and then 400 m to the southeast (at a 45 degree angle). If he has run at a constant speed, how far away is he from the starting position? \n" );
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Algebra.Com's Answer #193464 by edjones(8007) You can put this solution on YOUR website! s-a-s triangle \n" ); document.write( "a^2=b^2+c^2-2bc*cos(a) \n" ); document.write( "=300^2+400^2-2*300*400*cos(45) \n" ); document.write( "=90000+160000-120000sqrt(2) \n" ); document.write( "=80294.36 \n" ); document.write( "a=283.4 m \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |