document.write( "Question 262622: HAVING A PROBLEM WITH THIS SYSTEM OF EQUATIONS. NOT SURE I HAVE DONE IT RIGHT.\r
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document.write( "X+2Y+Z=2
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document.write( " 5X=Z
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document.write( " Y=-2X \n" );
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Algebra.Com's Answer #193441 by mananth(16946) You can put this solution on YOUR website! X+2Y+Z=2 ----1 \n" ); document.write( "5X=Z --------2 \n" ); document.write( "Y=-2X---------3\r \n" ); document.write( "\n" ); document.write( "substitute the value of z in eq 1\r \n" ); document.write( "\n" ); document.write( "x+2y+5x=2 \n" ); document.write( "6x+2y=2 ----a \n" ); document.write( "y+2x=0 ---------3 \n" ); document.write( "multiply eq. 3 by 2 \n" ); document.write( "2y+4x=0 ---------b\r \n" ); document.write( "\n" ); document.write( "solve equation a & b for x subtract b from a\r \n" ); document.write( "\n" ); document.write( "2x=2 \n" ); document.write( "x=1\r \n" ); document.write( "\n" ); document.write( "apply for y and z\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |