document.write( "Question 262615: Area of a sail. The area in square meters for a triangular
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document.write( "sail is given by A(x)= x^2+5x+6.
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document.write( "a) Find A(5).
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document.write( "b) If the height of the sail is x +3 meters, then what is
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document.write( "the length of the base of the sail?\r
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Algebra.Com's Answer #193435 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! Area of a sail. The area in square meters for a triangular \n" ); document.write( "sail is given by A(x)= x^2+5x+6. \n" ); document.write( "a) Find A(5). \n" ); document.write( "b) If the height of the sail is x +3 meters, then what is \n" ); document.write( "the length of the base of the sail? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A(5) = 5^2 + 5*5 + 6 so \n" ); document.write( "A(5) = 25 + 25 + 6 = 56\r \n" ); document.write( "\n" ); document.write( "The area of the triangle is 1/2*base*height.\r \n" ); document.write( "\n" ); document.write( "Let B be the base. Then we have \r \n" ); document.write( "\n" ); document.write( "A(x) = x^2 +5x + 6 = 1/2*B*(x+3)\r \n" ); document.write( "\n" ); document.write( "Multiply both sides by 2:\r \n" ); document.write( "\n" ); document.write( "2*(x^2 + 5x + 6) = B*(x+3)\r \n" ); document.write( "\n" ); document.write( "Factor the left side: \r \n" ); document.write( "\n" ); document.write( "2*(x+3)*(x+2) = B*(x+3)\r \n" ); document.write( "\n" ); document.write( "Divide both sides by (x+3)\r \n" ); document.write( "\n" ); document.write( "2*(x+2) = B \n" ); document.write( "B = 2x + 4\r \n" ); document.write( "\n" ); document.write( "If x=5, B = 14 \n" ); document.write( " |