document.write( "Question 262572: a 19 liter mixture consists by volume of one part juice, to 18 parts water. if x liters of juice and y liters of water are added to this mixture to make 54 liter mixture consisting my volume of 1 part juice, to two parts water what is the value of x? \n" ); document.write( "
Algebra.Com's Answer #193434 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a 19 liter mixture consists by volume of one part juice, to 18 parts water. \n" ); document.write( "if x liters of juice and y liters of water are added to this mixture to make 54 \n" ); document.write( " liter mixture consisting my volume of 1 part juice, to two parts water what is the value of x? \n" ); document.write( ": \n" ); document.write( "You see the original mixture had 1 liter of juice and 18 liters of water \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "2(x+1) = y + 18 \n" ); document.write( "2x + 2 = y + 18 \n" ); document.write( "2x = y + 18 - 2 \n" ); document.write( "2x = y + 16 \n" ); document.write( ": \n" ); document.write( "We know resulting amt was 19 liters and resulting amt is to be 54 liters \n" ); document.write( "Therefore \n" ); document.write( "x + y = 54 - 19 \n" ); document.write( "x + y = 35 \n" ); document.write( "y = (35-x) \n" ); document.write( "; \n" ); document.write( "Substitute (35-x) for y in the equation 2x = y + 16 \n" ); document.write( "2x = (35-x) + 16 \n" ); document.write( "2x + x = 35 + 16 \n" ); document.write( "3x = 51 \n" ); document.write( "x = \n" ); document.write( "x = 17 liters of juice \n" ); document.write( "and \n" ); document.write( "y = 35-17 \n" ); document.write( "y = 18 liters of water \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( " |