document.write( "Question 262572: a 19 liter mixture consists by volume of one part juice, to 18 parts water. if x liters of juice and y liters of water are added to this mixture to make 54 liter mixture consisting my volume of 1 part juice, to two parts water what is the value of x? \n" ); document.write( "
Algebra.Com's Answer #193434 by ankor@dixie-net.com(22740)\"\" \"About 
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a 19 liter mixture consists by volume of one part juice, to 18 parts water.
\n" ); document.write( "if x liters of juice and y liters of water are added to this mixture to make 54
\n" ); document.write( " liter mixture consisting my volume of 1 part juice, to two parts water what is the value of x?
\n" ); document.write( ":
\n" ); document.write( "You see the original mixture had 1 liter of juice and 18 liters of water
\n" ); document.write( ":
\n" ); document.write( "\"%28x+%2B+1%29%2F%28y+%2B+18%29\" = \"1%2F2\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "2(x+1) = y + 18
\n" ); document.write( "2x + 2 = y + 18
\n" ); document.write( "2x = y + 18 - 2
\n" ); document.write( "2x = y + 16
\n" ); document.write( ":
\n" ); document.write( "We know resulting amt was 19 liters and resulting amt is to be 54 liters
\n" ); document.write( "Therefore
\n" ); document.write( "x + y = 54 - 19
\n" ); document.write( "x + y = 35
\n" ); document.write( "y = (35-x)
\n" ); document.write( ";
\n" ); document.write( "Substitute (35-x) for y in the equation 2x = y + 16
\n" ); document.write( "2x = (35-x) + 16
\n" ); document.write( "2x + x = 35 + 16
\n" ); document.write( "3x = 51
\n" ); document.write( "x = \"51%2F3\"
\n" ); document.write( "x = 17 liters of juice
\n" ); document.write( "and
\n" ); document.write( "y = 35-17
\n" ); document.write( "y = 18 liters of water
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check:
\n" ); document.write( "\"%281+%2B+17%29%2F%2818+%2B+18%29\" = \"18%2F36\" = 1/2
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