document.write( "Question 262282: Len is planning a 3 hour trip down the Allenem River and back to his starting point. He knows he can paddle in still water at 3 mph and that the rate of the current is 2 mph. How much time can he spend going down stream? How far can he travel?
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Algebra.Com's Answer #193427 by ankor@dixie-net.com(22740)\"\" \"About 
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Len is planning a 3 hour trip down the Allenem River and back to his starting point.
\n" ); document.write( "He knows he can paddle in still water at 3 mph and that the rate of the current is 2 mph.
\n" ); document.write( " How much time can he spend going down stream? How far can he travel?
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\n" ); document.write( "Find his speed up and down stream
\n" ); document.write( "3-2 = 1 mph upstream
\n" ); document.write( "3+2 = 5 mph down stream
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\n" ); document.write( "Let d = distance he travels before he turns around
\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "Time upst + time down = 3 hrs
\n" ); document.write( "\"d%2F1\" + \"d%2F5\" = 3
\n" ); document.write( "Multiply equation by 5, results:
\n" ); document.write( "5d + d = 5(3)
\n" ); document.write( "6d = 15
\n" ); document.write( "d = \"15%2F6\"
\n" ); document.write( "d = 2.5 mi up stream and the same back
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\n" ); document.write( "Find the time downstream
\n" ); document.write( "2.5/5 = .5 hrs down stream
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\n" ); document.write( "Check solution
\n" ); document.write( "2.5/1 + 2.5/5 = 3 hrs \n" ); document.write( "
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