document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32833>Question 32833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> |12y/-3y2 power|  Please show how to figure this out </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19340 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> |12y/-3y2 power|\r<BR>\n" );
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document.write( "on division we get ....\r<BR>\n" );
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document.write( "| 4/ -3y|\r<BR>\n" );
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document.write( "and to put it into standarad from we get........\r<BR>\n" );
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document.write( "|-4/3y|\r<BR>\n" );
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document.write( " now as there is a sign of absolute value so we get..\r<BR>\n" );
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document.write( "4/3y\r<BR>\n" );
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document.write( "Hope this will help you \r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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