document.write( "Question 262427: sqrt3y + sqrt1 = 4\r
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document.write( "the square root sign is above 3y + 1 \n" );
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Algebra.Com's Answer #193341 by stanbon(75887) ![]() You can put this solution on YOUR website! sqrt(3y + 1) = 4 \n" ); document.write( "the square root sign is above 3y + 1 \n" ); document.write( "Square both sides to get: \n" ); document.write( "3y + 1 = 16 \n" ); document.write( "3y = 15 \n" ); document.write( "y = 3 \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |