document.write( "Question 32726: I'm fairly positive that this is the correct place for the question... I need some assistance in solving this 3rd grade polynome-equation:\r
\n" ); document.write( "\n" ); document.write( "x^3+10x^2+26x=0\r
\n" ); document.write( "\n" ); document.write( "I've gotten myself stuck in a bunch of mathematical gibberish which I'd rather not submit out of shame (*sobs*). Any help will be appreciated.
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Algebra.Com's Answer #19333 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"x%5E3%2B10x%5E2%2B26x+=+0\" Factor an x.
\n" ); document.write( "\"x%28x%5E2%2B10x%2B26%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"x+=+0\" and/or \"x%5E2%2B10x%2B26+=+0\"
\n" ); document.write( "Solve:
\n" ); document.write( "\"x%5E2%2B10x%2B26+=+0\" Solve using the quadratic formula:\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( "\"x=%28-10%2B-sqrt%2810%5E2-4%281%29%2826%29%29%29%2F2%281%29\"
\n" ); document.write( "\"x=%28-10%2B-sqrt%28100-104%29%29%2F2\"
\n" ); document.write( "\"x=%28-10%2B-sqrt%28-4%29%29%2F2\"
\n" ); document.write( "\"x=-5%2B-sqrt%28-1%29\"\r
\n" ); document.write( "\n" ); document.write( "The roots are:
\n" ); document.write( "x = 0
\n" ); document.write( "x = -5+i or -(5-i)
\n" ); document.write( "x = -5-i or -(5+i)
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