document.write( "Question 262324: Suppose the width of a certain rectangle is 1 inch more than 1/4 of its length. The perimeter of the rectangle is 72 inches find the length.\r
\n" ); document.write( "\n" ); document.write( "P=2L+2W
\n" ); document.write( "72=
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Algebra.Com's Answer #193323 by checkley77(12844)\"\" \"About 
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W=L/4+1
\n" ); document.write( "2L+2W=72
\n" ); document.write( "2L+2(L/4+1)=72
\n" ); document.write( "2L+L/2+2=72
\n" ); document.write( "2.5L=72-2
\n" ); document.write( "2.5L=70
\n" ); document.write( "L=70/2.5
\n" ); document.write( "L=28 ANS.
\n" ); document.write( "W=28/4+1
\n" ); document.write( "W=7+1=8 ANS.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*28=2*8=72
\n" ); document.write( "56+16=72
\n" ); document.write( "72=72
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