document.write( "Question 262392: I need help with this problem:\r
\n" ); document.write( "\n" ); document.write( "Write with positive exponents (3^-2 a^-2 b^5)over (c^-3 d^-4). \r
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Algebra.Com's Answer #193312 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's break this up:\r
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\n" ); document.write( "\n" ); document.write( "\"3%5E%28-2%29=1%2F3%5E2=1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E%28-2%29=1%2Fa%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"c%5E%28-3%29=1%2Fc%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"d%5E%28-4%29=1%2Fd%5E4\"\r
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\n" ); document.write( "\n" ); document.write( "So \"3%5E%28-2%29a%5E%28-2%29b%5E5=%281%2F9%29%281%2Fa%5E2%29b%5E5=%28b%5E5%29%2F%289a%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "and \"c%5E%28-3%29d%5E%28-4%29=%281%2Fc%5E3%29%281%2Fd%5E4%29=1%2F%28c%5E3d%5E4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Altogether, \r
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\n" ); document.write( "\n" ); document.write( "Now multiply by the reciprocal of the second fraction and simplify to get the final answer of \"%28b%5E5c%5E3d%5E4%29%2F%289a%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%283%5E%28-2%29a%5E%28-2%29b%5E5%29%2F%28c%5E%28-3%29d%5E%28-4%29%29\" simplifies to \"%28b%5E5c%5E3d%5E4%29%2F%289a%5E2%29\" where none of the variables can be equal to zero.\r
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\n" ); document.write( "\n" ); document.write( "In other words,
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