document.write( "Question 262137: A man 38 years old has a son 14 years old. How many years ago was the man seven times as old as his son? I also need the steps! \n" ); document.write( "
Algebra.Com's Answer #193295 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A man 38 years old has a son 14 years old. How many years ago was the man seven times as old as his son? I also need the steps!
\n" ); document.write( ":
\n" ); document.write( "let x = no. of years ago the man was 7 times the son
\n" ); document.write( ":
\n" ); document.write( "Man's age x yrs ago = 7 time son's age x years ago; write an equation for this
\n" ); document.write( "38 - x = 7(14 - x)
\n" ); document.write( "38 - x = 98 - 7x
\n" ); document.write( "-x + 7x = 98 - 38
\n" ); document.write( "6x = 60
\n" ); document.write( "x = \"60%2F6\"
\n" ); document.write( "x = 10 yrs ago, this was true
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check it:
\n" ); document.write( "38 - 10 = 7(14 - 10)
\n" ); document.write( "28 = 7(4)
\n" ); document.write( ":
\n" ); document.write( "Was this steps enough for you to understand it?
\n" ); document.write( " \n" ); document.write( "
\n" );