document.write( "Question 262353: What is the equation of the line that passes through (6,-4)and (3,2) \n" ); document.write( "

Algebra.Com's Answer #193277 by EMStelley(208) $\"\"$ $\"About$

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The first thing we need to determine here is the slope of the line. Remember that if you have two points (x1,y1) and (x2,y2), the slope is:\r
\n" ); document.write( "\n" ); document.write( " $\"m+=+%28y2-y1%29%2F%28x2-x1%29\"$ \r
\n" ); document.write( "\n" ); document.write( "So here, (x1,y1) is (6,-4) and (x2,y2) is (3,2), so the slope is:\r
\n" ); document.write( "\n" ); document.write( " $\"m+=+%282-%28-4%29%29%2F%283-6%29+=+6%2F-3+=+-2\"$ \r
\n" ); document.write( "\n" ); document.write( "Now, remember that if you have a point (x1,y1) and a slope m, the equation of the line is:\r
\n" ); document.write( "\n" ); document.write( "y-y1 = m(x-x1)\r
\n" ); document.write( "\n" ); document.write( "So we have\r
\n" ); document.write( "\n" ); document.write( "y-(-4) = -2(x-6)\r
\n" ); document.write( "\n" ); document.write( "y+4 = -2x+12\r
\n" ); document.write( "\n" ); document.write( "y = -2x + 8 \n" ); document.write( "

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