document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262343>Question 262343</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm solving horizontal curve where the radius is 4000m and the subtending angle is 19 degrees. I understand that the formula for CL is 2* Radius sin ( tetha/2). so is that 2*(4000m)sin 19 degrees  from there how do i find the arc length S. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193269 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm solving horizontal curve where the radius is 4000m and the subtending angle is 19 degrees. I understand that the formula for CL is 2* Radius sin ( tetha/2). so is that 2*(4000m)sin 19 degrees from there how do i find the arc length S.<BR>\n" );
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document.write( "If I understand it, you're looking for the length of the arc subtended by a 19 deg angle, with a radius of 4000 meters.<BR>\n" );
document.write( "That's 2*pi*r*(19/360)<BR>\n" );
document.write( "=~ 663.225 meters </SPAN>\n" );
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