document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262308>Question 262308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve for x in the following problem.\r<BR>\n" );
document.write( "\n" );
document.write( "2(3x-1) -4(2-x) = 3x+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193246 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, Let's first expand 2(3x-1) -4(2-x) = 3x+1 this out to be:<BR>\n" );
document.write( "6x-2-8+4x=3x+1 This can be rewritten as:<BR>\n" );
document.write( "10x-10=3x+1 Subtract 3x from both sides and add 10 to both sides to give us:<BR>\n" );
document.write( "7x=11 Divide 7 into both sides will be:<BR>\n" );
document.write( "x=11/7<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "You can check it out by plugging the answer into the original equation. <BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "Check out a new book I wrote at:<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );