document.write( "Question 262003: Find a two-decimal-place number between 0 and 1 such that the sum of its digits is 9 and such that if the digits are reversed the number is increased by .27. \n" ); document.write( "
Algebra.Com's Answer #193223 by ankor@dixie-net.com(22740)\"\" \"About 
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Find a two-decimal-place number between 0 and 1 such that the sum of its digits is 9 and such that if the digits are reversed the number is increased by .27.
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\n" ); document.write( "Let x = 10th digit
\n" ); document.write( "Let y = 100th digit
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\n" ); document.write( "\"a two-decimal-place number between 0 and 1 such that the sum of its digits is 9\"
\n" ); document.write( "x + y = 9
\n" ); document.write( ":
\n" ); document.write( "\"if the digits are reversed the number is increased by .27
\n" ); document.write( ".1y + .01x = .1x + .01y + .27
\n" ); document.write( ":
\n" ); document.write( "multiply by 100, get rid of those annoying decimals
\n" ); document.write( "10y + x = 10x + y + 27
\n" ); document.write( "10y - y = 10x - x - 27
\n" ); document.write( "9y = 9x - 27
\n" ); document.write( "simplify, divide by 9
\n" ); document.write( "y = x + 3
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\n" ); document.write( "In the 1st equation, x + y = 9, replace y with (x+3)
\n" ); document.write( "x + x + 3 = 9
\n" ); document.write( "2x = 9 - 3
\n" ); document.write( "2x = 6
\n" ); document.write( "x = 3
\n" ); document.write( "then
\n" ); document.write( "y = 3 + 3
\n" ); document.write( "y = 6
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\n" ); document.write( "The two decimal number: .36 \n" ); document.write( "
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