document.write( "Question 262256: solve for x, y, and z in the following systems of three equations:\r
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document.write( "10x+y+z=603
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document.write( "8x+2y+z=603
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document.write( "20x-10y-2z=-6 \n" );
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Algebra.Com's Answer #193217 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! x=50 y=100 z=3\r \n" ); document.write( "\n" ); document.write( "10x+y+z=603 \n" ); document.write( "8x+2y+z=603 \n" ); document.write( "20x-10y-2z=-6 \n" ); document.write( "we can set the first two equal to each other \n" ); document.write( "10x+y+z=8x+2y+z \n" ); document.write( "subtract z \n" ); document.write( "10x+y=8x+2y \n" ); document.write( "2x=y \n" ); document.write( "multiply first by 2 \n" ); document.write( "20x+2y+2z=1206 \n" ); document.write( "20x-10y-2z=-6 \n" ); document.write( "subtract third from new first \n" ); document.write( "12y+4z=1212 \n" ); document.write( "divide by 4 \n" ); document.write( "3y+z=303 \n" ); document.write( "8x+2y+z=603 \n" ); document.write( "add 300 \n" ); document.write( "3y+z+300=603 \n" ); document.write( "8x+2y+z=3y+z+300 \n" ); document.write( "8x=y+300 \n" ); document.write( "2x=y \n" ); document.write( "8x=2x+300 \n" ); document.write( "6x=300 \n" ); document.write( "x=50 \n" ); document.write( "2x=y \n" ); document.write( "y=100 \n" ); document.write( "3y+z=303 \n" ); document.write( "300+z=303 \n" ); document.write( "z=3 \n" ); document.write( " \n" ); document.write( " |