document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262247>Question 262247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not understanding how to express each power asa radical,then evaluate.   (-7776)^2/5 <BR>\n" );
document.write( "I go over other examples but not understanding how they get the last bit of the answer on  the calculator.<BR>\n" );
document.write( "They have as an example..... (-243)^1/5=5&#8730;-243   = -3    <BR>\n" );
document.write( "not sure how they got =-3? very stumped.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193189 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-3)^5 = -243<BR>\n" );
document.write( "So the 5th root of -243 is -3.<BR>\n" );
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document.write( "6^5 = 7776<BR>\n" );
document.write( "Odd powers of negatives are negative.<BR>\n" );
document.write( "(-6)^5 = -7776<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "(-7776)^(1/5) = -6<BR>\n" );
document.write( "(-6)^2 = +36<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Calculators use logs for internal calculation, which don't handle negative numbers in most cases (most calculators).<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );