document.write( "Question 32482: Prove the following identity:\r
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document.write( "cos^4theta + 2cos^2theta sin^2theta + sin^4theta = 1 \n" );
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Algebra.Com's Answer #19318 by sarah_adam(201) ![]() You can put this solution on YOUR website! Here iam replacing theta with x \n" ); document.write( "so your question becomes cos^4x + 2cos^2x sin^2x + sin^4x which can be also written as: \n" ); document.write( "(cos^2x)^2+2(co^2x)(sin^2x)+ (sin^2x)^2 \n" ); document.write( "If you observe carefully the equation is in the form of a^2+2*a*b+b^2 \n" ); document.write( "i.e., (a+b)^2 \n" ); document.write( "where a = cos^2x and b = Sin^2x \n" ); document.write( "therfore the equation can be simplified into (cos^2x +sin^2x)^2 \n" ); document.write( "But we know cos^2x +sin^2x = 1 \n" ); document.write( "therfore (cos^2x +sin^2x)^2 = (1)^2 = 1 \n" ); document.write( "Hence Proved \n" ); document.write( " |