document.write( "Question 262216: ind three consecutive odd integers such that the product of the first and second exceeds the third by 8. \n" ); document.write( "
Algebra.Com's Answer #193173 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
three consecutive odd integers such that the product of the first and second exceeds the third by 8
\n" ); document.write( ".
\n" ); document.write( "Let x = first consecutive odd integer
\n" ); document.write( "then
\n" ); document.write( "x+2 = second consecutive odd integer
\n" ); document.write( "x+4 = third consecutive odd integer
\n" ); document.write( ".
\n" ); document.write( "x(x+2) = (x+4) + 8
\n" ); document.write( "x^2 + 2x = x + 12
\n" ); document.write( "x^2 +x -12 = 0
\n" ); document.write( "(x-3)(x+4) = 0
\n" ); document.write( "x = {3,-4}
\n" ); document.write( ".
\n" ); document.write( "Since -4 is an even number toss out the solution.
\n" ); document.write( ".
\n" ); document.write( "The three odd integers:
\n" ); document.write( "3,5,7\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );