document.write( "Question 262214: an ant can walk 1 cm/s faster than a beetle. from points that are 50cm apart the ant and the beettle start walking directly towards each other and meet in 10 secs. how fast does each of them walk. asume they both started walking at the same time \n" ); document.write( "
Algebra.Com's Answer #193161 by palanisamy(496)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed of a beetle = x cm/s \n" ); document.write( "Then,the speed of the ant = x+1 cm/s \n" ); document.write( "Given, from points that are 50cm apart the ant and the beettle start walking directly towards each other and meet in 10 secs. \n" ); document.write( "speed*time = distance \n" ); document.write( "(x+x+1)*10 = 50 \n" ); document.write( "Dividing by 10, \n" ); document.write( " 2x+1 = 5 \n" ); document.write( " 2x = 5-1 \n" ); document.write( " 2x = 4 \n" ); document.write( " x = 2 \n" ); document.write( "Therefore, the speed of a beetle = 2 cm/s \n" ); document.write( "And,the speed of the ant = 2+1 = 3 cm/s \n" ); document.write( " \n" ); document.write( " |