document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262205>Question 262205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the equation 3(4x-9)=x+100.  So far I have done two steps and then i am completely lost?  My first step I got 12x-27=x+100, then the second step I got 12x=x+127, now I cant figure out how do I divided the 12 with the x or the 127? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193153 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your equation is:\r<BR>\n" );
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document.write( "3*(4*x-9) = x+100\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "12*x - 27 = x + 100\r<BR>\n" );
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document.write( "so far you did good.\r<BR>\n" );
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document.write( "add 27 to both sides of this equation to get:\r<BR>\n" );
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document.write( "12*x = x + 100 + 27\r<BR>\n" );
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document.write( "you simplified this to get:\r<BR>\n" );
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document.write( "12*x = x + 127\r<BR>\n" );
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document.write( "so far you still did good.\r<BR>\n" );
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document.write( "you needed to get all the x's on one side of the equation.\r<BR>\n" );
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document.write( "you do that by subtracting x from both sides of the equation to get:\r<BR>\n" );
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document.write( "12*x - x = 127\r<BR>\n" );
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document.write( "simplify that to get:\r<BR>\n" );
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document.write( "11*x = 127\r<BR>\n" );
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document.write( "now you divide both sides of the equation by 11 to get:\r<BR>\n" );
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document.write( "x = 127 / 11 = 11.54545454\r<BR>\n" );
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document.write( "that should be your answer.\r<BR>\n" );
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document.write( "you confirm by substituting for x in the original equation.\r<BR>\n" );
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document.write( "original equation is:\r<BR>\n" );
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document.write( "3*(4*x-9) = x+100\r<BR>\n" );
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document.write( "substitute 11.54545454 for x to get:\r<BR>\n" );
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document.write( "3*(4*11.54545454 - 9) = 11.54545454 + 100\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "3 * (37.18181818) = 111.54545454\r<BR>\n" );
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document.write( "simplify further to get:\r<BR>\n" );
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document.write( "111.54545454 = 111.54545454 confirming that the value calculated for x is good.\r<BR>\n" );
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document.write( "the numbers displayed on the calculator are usually rounded to the nearest 8 decimal places or thereabouts.\r<BR>\n" );
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document.write( "I used the internally stored numbers which are carried out to more digits than can be displayed.\r<BR>\n" );
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document.write( "If you just use the 8 or so decimal places displayed, your answer will be very close.\r<BR>\n" );
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document.write( "If you then round to the nearest 1 or 2 decimal places, your answer should be right on.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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