document.write( "Question 262207: suppose that the width of a certain rectangle is 2 inches more than one fourth of its length. the perimeter is 54 inches. find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #193152 by palanisamy(496)\"\" \"About 
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Let the length = x
\n" ); document.write( "Given, the width of a certain rectangle is 2 inches more than one fourth of its length.
\n" ); document.write( "So, width = x/4 +2
\n" ); document.write( "Perimeter is 2*(x+x/4+2) = 54
\n" ); document.write( " 2x+x/2+4 = 54
\n" ); document.write( " (4x+x)/2 = 54-4
\n" ); document.write( " 5x = 2*50
\n" ); document.write( " 5x = 100
\n" ); document.write( " x = 100/5
\n" ); document.write( " x = 20 inches
\n" ); document.write( "Therefore the length = 20
\n" ); document.write( " width = x/4+2 = 20/4+2 = 5+2 = 7 inches
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