document.write( "Question 262207: suppose that the width of a certain rectangle is 2 inches more than one fourth of its length. the perimeter is 54 inches. find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #193152 by palanisamy(496)![]() ![]() ![]() You can put this solution on YOUR website! Let the length = x \n" ); document.write( "Given, the width of a certain rectangle is 2 inches more than one fourth of its length. \n" ); document.write( "So, width = x/4 +2 \n" ); document.write( "Perimeter is 2*(x+x/4+2) = 54 \n" ); document.write( " 2x+x/2+4 = 54 \n" ); document.write( " (4x+x)/2 = 54-4 \n" ); document.write( " 5x = 2*50 \n" ); document.write( " 5x = 100 \n" ); document.write( " x = 100/5 \n" ); document.write( " x = 20 inches \n" ); document.write( "Therefore the length = 20 \n" ); document.write( " width = x/4+2 = 20/4+2 = 5+2 = 7 inches \n" ); document.write( " \n" ); document.write( " |