document.write( "Question 262186: Chris starts his run at 7:00 a.m. He runs at a rate of 4 miles per hour. His course takes him three miles out and then back along the same path. John runs at a rate of 6 miles per hour, starting at 7:10 a.m., and he runs the same course. How many minutes elapse between the time John finishes and the time Chris finishes? \n" ); document.write( "

Algebra.Com's Answer #193139 by texttutoring(324) $\"\"$ $\"About$

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We will use the equation d=vt, where d=distance, v=velocity (or speed), and t=time.\r
\n" ); document.write( "\n" ); document.write( "Chris:
\n" ); document.write( "d = 3 + 3 = 6 miles
\n" ); document.write( "v = 4 mph
\n" ); document.write( "t = ?\r
\n" ); document.write( "\n" ); document.write( "d=vt
\n" ); document.write( "6=4*t
\n" ); document.write( "t=6/4
\n" ); document.write( "t=1.5 hours\r
\n" ); document.write( "\n" ); document.write( "John:
\n" ); document.write( "d = 3 + 3 = 6 miles
\n" ); document.write( "v = 6 mph
\n" ); document.write( "t = ?\r
\n" ); document.write( "\n" ); document.write( "d=vt
\n" ); document.write( "6=6*t
\n" ); document.write( "t=6/6
\n" ); document.write( "t=1 hour\r
\n" ); document.write( "\n" ); document.write( "Chris started at 7:00am, so he will end at 8:30am.
\n" ); document.write( "John started at 7:10am, so he will end at 8:10am.\r
\n" ); document.write( "\n" ); document.write( "20 minutes will elapse after John finishes. \n" ); document.write( "

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