document.write( "Question 262168: The tens digit of a two digit number is 3 times greater than the units digit. Eight times the sum of the digits is 1 less than the number. Find the number.\r
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document.write( "I've been provided the answer and have ran through numerous equations, but can't seem to get the correct equation that solves for the answer.\r
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document.write( "I appreciate any help you can provide... \n" );
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Algebra.Com's Answer #193136 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! let t=ten's digit and u equal units digit. \n" ); document.write( "t=3u \n" ); document.write( "8(t+u)=10t+u-1 \n" ); document.write( "8t+8u=10t+u-1 \n" ); document.write( "7u=2t-1 \n" ); document.write( "7u=2*(3u)-1 \n" ); document.write( "7u=6u-1 \n" ); document.write( "u=-1 \n" ); document.write( "t=-3 \n" ); document.write( "the number is -31 \n" ); document.write( "check \n" ); document.write( "8(-3-1)=-31=1 \n" ); document.write( "8*-4=-32 \n" ); document.write( "-32=-32 \n" ); document.write( "So why are you hiding the answer you were given?\r \n" ); document.write( "\n" ); document.write( "It turns out that the original problem says three greater and not three times greater \n" ); document.write( "so picking up the problem\r \n" ); document.write( "\n" ); document.write( "7u=2t-1 \n" ); document.write( "t=3+u \n" ); document.write( "7u=2(3+u)-1 \n" ); document.write( "7u=6 +2u-1 \n" ); document.write( "5u=5 \n" ); document.write( "u=1 \n" ); document.write( "t=3+u \n" ); document.write( "t=3+1 \n" ); document.write( "t=4 \n" ); document.write( "check \n" ); document.write( "8*(4+1)=41-1 \n" ); document.write( "40=40 \n" ); document.write( "ok \n" ); document.write( " \n" ); document.write( " |