document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262173>Question 262173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of the page numbers on two facing pages of a book is 156.  Find the page numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193125 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193125\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The pages are facing each other, so they are consecutive numbers:\r<BR>\n" );
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document.write( "Let x = the first page number<BR>\n" );
document.write( "    y = the second page number\r<BR>\n" );
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document.write( "The second page number is just 1 more than the first, because they are consecutive numbers:\r<BR>\n" );
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document.write( "x+1 = y\r<BR>\n" );
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document.write( "We also know that the products of the numbers is equal to 156:\r<BR>\n" );
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document.write( "xy = 156\r<BR>\n" );
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document.write( "Now we will sub y = x+1 into the second equation:\r<BR>\n" );
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document.write( "x(x+1) = 156<BR>\n" );
document.write( "x^2 + x = 156<BR>\n" );
document.write( "x^2 + x - 156 = 0\r<BR>\n" );
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document.write( "Factoring (or using the quadratic formula) gives us:\r<BR>\n" );
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document.write( "(x+13)(x-12) = 0\r<BR>\n" );
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document.write( "x = - 13, or x = 12.\r<BR>\n" );
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document.write( "A page number can't be negative, so we will choose x=12.\r<BR>\n" );
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document.write( "This means that the second page must be page 13.\r<BR>\n" );
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document.write( "So the first page is 12, and the facing page is 13. </SPAN>\n" );
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