document.write( "Question 262176: what is the slope of y=12? \n" ); document.write( "

Algebra.Com's Answer #193124 by texttutoring(324) $\"\"$ $\"About$

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That is just a straight horizontal line at y=12.\r
\n" ); document.write( "\n" ); document.write( "Remember that:\r
\n" ); document.write( "\n" ); document.write( " $\"slope+=+%28y2-y1%29%2F%28x2-x1%29\"$ \r
\n" ); document.write( "\n" ); document.write( "and we know that:\r
\n" ); document.write( "\n" ); document.write( " $\"y2-y1+=+12+-+12+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"slope+=+0%2F%28x2-x1%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Zero divided by any number is always equal to zero.\r
\n" ); document.write( "\n" ); document.write( " $\"slope+=+0+\"$ \r
\n" ); document.write( "\n" ); document.write( "The slope of a horizontal line is 0. \n" ); document.write( "

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