document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32887>Question 32887</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A = 1/2h(B+b)\r<BR>\n" );
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document.write( "area of a trapezoid\r<BR>\n" );
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document.write( "solve for b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19311 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> area of a trapezoid : A = 1/2 * h *(B+b) where  B and b are the lengths of the two parallel bases of a trapezoid, and h is its height\r<BR>\n" );
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document.write( " A = 1/2 * h *(B+b)<BR>\n" );
document.write( " 2A/h = B + b<BR>\n" );
document.write( "Therefore b = 2A/h - B </SPAN>\n" );
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