document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=262069>Question 262069</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the digits of a two-digit number is 14. if the digits are reversed, the new number is 18 less than the original number. find original number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #193084 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=193084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number be xy<BR>\n" );
document.write( "Given, x+y = 14   ...(1)<BR>\n" );
document.write( "Also,if the digits are reversed, the new number is 18 less than the original number.<BR>\n" );
document.write( "        10y+x = 10x+y-18<BR>\n" );
document.write( "        10y+x-10x-y = -18<BR>\n" );
document.write( "        9y-9x = -18<BR>\n" );
document.write( "        y-x = -2    ...(2)<BR>\n" );
document.write( "(1)+(2) => 2y = 12<BR>\n" );
document.write( "           y = 6<BR>\n" );
document.write( "(1)=>  x+6 = 14<BR>\n" );
document.write( "       x = 14-6=8<BR>\n" );
document.write( "So the required number is 86 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );