document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32806>Question 32806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much water must be added to 180 grams of a solution that is 35% acetic acid to produce a solution that is 10% acetic acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19306 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the amount of water added be \"x\".<BR>\n" );
document.write( "Start: 0.65(180 grs.)= 117 grs. of water<BR>\n" );
document.write( "Add: x grams of water<BR>\n" );
document.write( "End up with: 0.9(180+x) grs of water<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "water + water = water<BR>\n" );
document.write( "117+x= 0.9(180+x)<BR>\n" );
document.write( "117+x=162+0.9x<BR>\n" );
document.write( "0.10x=45<BR>\n" );
document.write( "   x= 450 grams of water (amount of water added)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );